请问有高手可以帮帮忙做基于FPGA的中值滤波C程序仿真

hyp7617 · 发表于 2011-4-16 19:24:55

本帖最后由 hyp7617 于 2011-4-16 19:48 编辑

拜托了，各位高手

基本步骤我知道

三是在后面时钟、什么引脚设置的时候就不知所措了

谢谢各位高手了

我做毕业设计，需要仿真截图

QQ 992501270

是VerilogHDL语言的程序，已通过。

module median(clk,reset,load,din,mult,dout,over,a3,b3,c3,a2,b2,c2,a1,b1,c1);
input clk;
input reset;
input load; //load是控制信号，load为高，接收cpu提供的数据
input [7:0]din;
input [2:0]mult; //信号放大的倍数
output [7:0]dout;
output over; //当处理完一个点时产生一个时钟周期宽度的信号。
reg over;
output [7:0]a1,a2,a3,b1,b2,b3,c1,c2,c3;
reg [3:0]state;
reg [3:0]cur_state;
reg [10:0]img_x;
reg [1:0]img_y;
reg [10:0]pix;
reg [10:0]piy;
reg we0,we1,we2;
reg run_edge;
reg [10:0]addr;
reg [7:0]wrdata;
wire [7:0]rddata0,rddata1,rddata2;
reg [7:0]a_max,a_mid,a_min,b_max,b_mid,b_min,c_max,c_mid,c_min;
reg [7:0]max,mid,min,mid_mid,mid_max,mid_min;
reg [7:0]q_max,q_mid,q_min;
reg [7:0]d0,d1,d2,d3;
reg sum0,sum1,sum2,sum3;
reg [2:0]sum;
reg [9:0]temp0;
reg [7:0]temp;
reg [7:0]a1,a2,a3,b1,b2,b3,c1,c2,c3;
reg en;
parameter s0 = 4'd0,
s1 = 4'd1,
s2 = 4'd2,
s3 = 4'd3,
s4 = 4'd4,
s5 = 4'd5,
s6 = 4'd6 ,
s7 = 4'd7,
s8 = 4'd8,
s9 = 4'd9,
s10 = 4'd10,
s11 = 4'd11,
s12 = 4'd12,
s13 = 4'd13,
s14 = 4'd14,
s15 = 4'd15;
assign dout = temp;
always @(posedge clk or negedge reset)
begin
if (reset == 0)
begin
en <= 1;
over <= 1'b0;
img_x <= 11'd0;
img_y <= 2'd0;
we0 <= 1'b0;
we1 <= 1'b0;
we2 <= 1'b0;
pix <= 11'd0;
piy <= 2'd0;
run_edge <= 1'b0;
state <= s0;
cur_state <= s0;
end
else
begin
if (load & en)
begin
case (state)
s0:begin
if(img_x < 11'd1728)
begin
addr <= img_x;
state <= s0;
wrdata <= din;
img_x <= img_x + 11'd1;
if (img_y == 0)
we0 = 1;
else if(img_y == 1)
we1 = 1'b1;
else
we2 = 1'b1;
end
else
begin
state <=s1;
img_x <= 11'd0;
we0 <= 1'b0;
we1 <= 1'b0;
we2 <= 1'b0;
end
end
s1:begin
addr <= pix;
pix <= pix + 11'd1;
en <= 0;
run_edge <= 1'b1;
if (piy == 2'd0)
begin
cur_state <= s0;
a3 <= rddata0;
b3 <= rddata1;
c3 <= rddata2;
end
else if (piy == 2'd1)
begin
cur_state <= s1;
a3 <= rddata2;
b3 <= rddata0;
c3 <= rddata1;
end
else
begin
cur_state <= s2;
a3 <= rddata1;
b3 <= rddata2;
c3 <= rddata0;
end
end
endcase
end
else if (run_edge & !load)
begin
case (cur_state)
s0:begin
piy = 2'd0;
a1 <= a2;
b1 <= b2;
c1 <= c2;
a2 <= a3;
b2 <= b3;
c2 <= c3;
a3 <= rddata0;
b3 <= rddata1;
c3 <= rddata2;
cur_state <= s3;
end
s1:begin
piy = 2'd1;
a1 <= a2;
b1 <= b2;
c1 <= c2;
a2 <= a3;
b2 <= b3;
c2 <= c3;
a3 <= rddata2;
b3 <= rddata0;
c3 <= rddata1;
cur_state <= s3;
end
s2:begin
piy <= 2'd2;
a1 <= a2;
b1 <= b2;
c1 <= c2;
a2 <= a3;
b2 <= b3;
c2 <= c3;
a3 <= rddata1;
b3 <= rddata2;
c3 <= rddata0;
cur_state<= s3;
end
s3:begin
d0 <= (b2 > a2 ) ? (b2 - a2) : (a2 - b2);
d1 <= (b2 > b1 ) ? (b2 - b1) : (b1 - b2);
d2 <= (b2 > b3 ) ? (b2 - b3) : (b3 - b2);
d3 <= (b2 > c2 ) ? (b2 - c2) : (c2 - b2);
cur_state <= s4;
end
s4:begin
sum0 <= (d0 > 4) ? 1'b0 : 1'b1;
sum1 <= (d1 > 4) ? 1'b0 : 1'b1;
sum2 <= (d2 > 4) ? 1'b0 : 1'b1;
sum3 <= (d3 > 4) ? 1'b0 : 1'b1;
cur_state <= s5;
end
s5:begin
sum <= (sum0 + sum1) + (sum2 + sum3);
cur_state <= s6;
end
s6:begin
if ( (sum > 3'd1) && (sum < 3'd4) )
begin
//edge_out = 0; //low edge ,and not to disposal
cur_state <= s13;
q_mid <= b2;
end
else
//edge_out = 1; //high need to median
cur_state <= s7;
end
s7:begin
if (a1>a2)
begin
a_max<=a1;
a_min<=a2;
end
else
begin
a_max<=a2;
a_min<=a1;
end
if (b1 > b2)
begin
b_max<=b1;
b_min<=b2;
end
else
begin
b_max<=b2;
b_min<=b1;
end
if(c1>c2)
begin
c_max<=c1;
c_min<=c2;
end
else
begin
c_max<=c2;
c_min<=c1;
end
cur_state<=s8;
end
s8:begin
if (a3>a_max)
begin
a_max<=a3;
a_mid<=a_max;
a_min<=a_min;
end
else
begin
if (a3>a_min)
begin
a_max<=a_max;
a_mid<=a3;
a_min<=a_min;
end
else
begin
a_max<=a_max;
a_mid<=a_min;
a_min<=a3;
end
end
if (b3>b_max)
begin
b_max<=b3;
b_mid<=b_max;
b_min<=b_min;
end
else
begin
if(b3>b_min)
begin
b_max<=b_max;
b_mid<=b3;
b_min<=b_min;
end
else
begin
b_max<=b_max;
b_mid<=b_min;
b_min<=b3;
end
end
if(c3>c_max)
begin
c_max<=c3;
c_mid<=c_max;
c_min<=c_min;
end
else
begin
if(c3>c_min)
begin
c_max<=c_max;
c_mid<=c3;
c_min<=c_min;
end
else
begin
c_max<=c_max;
c_mid<=c_min;
c_min<=c3;
end
end
cur_state<=s9;
end
s9:begin
if (a_max>b_max)
max<=b_max;
else
max<=a_max;
if (a_mid>b_mid)
begin
mid_max<=a_mid;
mid_min<=b_mid;
end
else
begin
mid_max<=b_mid;
mid_min<=a_mid;
end
if (a_min>b_min)
min<=a_min;
else
min<=b_min;
cur_state<=s10;
end
s10:begin
if (c_mid > mid_max)
mid<=mid_max;
else
begin
if (c_mid<mid_min)
mid<=mid_min;
else
mid<=c_mid;
end
if (c_max>max)
max<=max;
else
max<=c_max;
if (c_min>min)
min<=c_min;
else
min<=min;
cur_state<=s11;
end
s11:begin
if (max>mid)
begin
q_max<=max;
q_min<=mid;
end
else
begin
q_max<=mid;
q_min<=max;
end
cur_state<=s12;
end
s12:begin
if (min>q_max)
q_mid<=q_max;
else
begin
if (min<q_min)
q_mid<=q_min;
else
q_mid<=min; //q_mid is the mid which to replace the initial number
end
cur_state <= s13;
end
s13:begin
temp0 <= q_mid * mult;
cur_state <= s14;
end
s14:begin
over <= 1;
if (temp0 > 8'd255)
temp <= 8'd255;
else
temp <= temp0[7:0];
cur_state <= s15;
end
s15:begin
over <= 0;
if (pix == 11'd1728)
begin
run_edge <= 0;
state <= s0;
en <=1;
pix <= 0;
if (piy == 0)
piy = 2'd1;
else if (piy == 1)
piy = 2'd2;
else
piy = 2'd0;
if (img_y == 0)
img_y = 1;
else if (img_y == 1)
img_y = 2;
else
img_y =0;
end
else
begin
pix <= pix + 2'd1;
if (piy == 2'd0)
cur_state <= s0;
else if (piy == 2'd1)
cur_state <= 2'd1;
else
cur_state <= 2'd2;
addr <= pix;
end
end
endcase
end
end
end
ram r1(clk,we0,addr,wrdata,rddata0);
ram r2(clk,we1,addr,wrdata,rddata1);
ram r3(clk,we2,addr,wrdata,rddata2);
endmodule
module ram(clk,we,addr,wrdata,rddata);
output [7:0] rddata;
input [10:0] addr;
input [7:0] wrdata;
input we, clk;
reg [10:0] addr_reg;
reg [7:0] mem [1727:0];
always @ (posedge clk)
begin
if (we) mem[addr] <= wrdata;
addr_reg <= addr;
end
assign rddata = mem[addr_reg];
endmodule

复制代码

iFPGA · 发表于 2011-4-17 02:28:17

虽然很简单，但是老哥我上班太忙，没有时间弄这些东西

hng1123 · 发表于 2011-4-17 10:26:54

自己做毕业设计，

hyp7617 · 发表于 2011-4-18 23:48:32

你们都酸了吧
这可是研究生的论文设计
我们老师把它作为我们的本科毕业设计
我只能服了他了

tjxgz · 发表于 2011-5-25 15:24:56

哪位大哥嫩解释一下啊

wywhust · 发表于 2011-5-25 22:38:54

用verilog不就可以仿真了吗，为什么要用c·······qq：774592087

		自动登录	找回密码
密码			我要注册

请问有高手可以帮帮忙做基于FPGA的中值滤波C程序仿真

站长推荐 /1